Re: gp: subst(x^2+x+1,x^2+1,x)

[Bill Daly <bill.daly@tradition-ny.com>]

On Mon, 10 Feb 2003, Michael Somos wrote:
> ? subst(x^2+x+1,x^2+1,x)
> %1 = 2*x
>
> Is it supposed to do that?

This is consistent with Mod(x^2+x+1,x^2-x+1) == Mod(2*x,x^2-x+1).

Regards, Bill



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