Bill Allombert on Tue, 09 Mar 2004 19:12:36 +0100 |
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freeall() does not free members_hash ? |
Hello PARI-dev, During the new parser experiment, I found that freeall() probably miss a free((void *)members_hash); (By the way, gcc give a warning in subgroups.c line 290) Cheers, Bill. PS: I have updated the experimental parser: <http://pari.math.u-bordeaux.fr/~bill/pari-2.2.8.bill-2.tar.gz> It support break(), return() and %n. it pass the test-suite if we exclude all the getheap calls since I have removed the kludges.