Jeroen Demeyer on Wed, 28 Oct 2015 12:22:25 +0100 |
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qfgaussred() for singular matrices |
Hello,it is not clear to me if qfgaussred() is officially supported for singular matrices.
I am asking because of this unexpected output: gp> qfgaussred([1,1;1,1]) %1 = [1 1] [1 0]The problem is that the new basis vectors are (1,1) and (1,1) which are not linearly independent. It would be useful if the vectors
x_i + sum_{i != j} a_ij x_j(where x_i is a given basis) would always form a new basis, even in the singular case.
Jeroen.