| Bill Allombert on Tue, 19 Dec 2023 10:50:30 +0100 |
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| Re: Finding bitprecision |
On Mon, Dec 18, 2023 at 10:20:54PM -0800, Ilya Zakharevich wrote: > Should not there be O(1) way to find the current localbitprecision()? > > (22:17) gp > localprec(10000); my(s); for(n=1,100000, s+=bitprecision(1.)); > time = 78 ms. > (22:17) gp > localprec(1000000); my(s); for(n=1,100000, s+=bitprecision(1.)); > time = 2,121 ms. Yes, it is called getlocalbitprec(). Cheers, Bill