Dr. Robert Harley on Tue, 6 May 2003 17:30:00 +0200 (CEST) |
[Date Prev] [Date Next] [Thread Prev] [Thread Next] [Date Index] [Thread Index]
Re: Rademacher formula for p(n) with PARI |
Another remark: The following formula (which appears to be more efficient) for the first factor of the terms appears (essentially) in Lehmer's paper: partfac1(q, n) = local(rb); sum(r = 0, q-1, if(gcd(r, q)>1, 0, rb = lift(1/Mod(r, q)); cos(if(q%2, -24*n*r-6*q*kronecker(-r, q)-3*q*(q-3)-(sqr(q)-1)*(2*r+rb-sqr(r)*rb), -24*n*r-6*q*kronecker(-q, r)+r*(q+1)*(q+2)+(sqr(q)-1)*(sqr(r)-1)*rb)*Pi/12/q))) There are also some interesting multiplication theorems to reduce to the case where q is a prime power... surely these would be useful for implementation. :-/ Bye, Rob. .-. .-. / \ .-. .-. / \ / \ / \ .-. _ .-. / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / `-' `-' \ / \ / \ \ / `-' `-' \ / `-' `-'