Karim Belabas on Mon, 22 Oct 2012 22:31:44 +0200 |
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Re: exp is faster the second time round |
* Dirk Laurie [2012-10-22 22:19]: > With \p 1000000, it takes about a minute to compute exp > on my laptop. Immediate afterwards, it takes about 30 seconds. > > Obviously some constants are being memoized. Which > constants are these? log(2) Since exp(x - k log(2)) = x / 2^k, argument reduction allows us to assume that |x| <= log(2)/2 Cheers, K.B. -- Karim Belabas, IMB (UMR 5251) Tel: (+33) (0)5 40 00 26 17 Universite Bordeaux 1 Fax: (+33) (0)5 40 00 69 50 351, cours de la Liberation http://www.math.u-bordeaux1.fr/~belabas/ F-33405 Talence (France) http://pari.math.u-bordeaux1.fr/ [PARI/GP] `