| Karim Belabas on Tue, 09 Sep 2014 21:04:31 +0200 |
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| Re: Specialize bivariate FpXY (C library) |
* Dan Nichols [2014-09-09 19:43]:
> Given an FpXY f(x,y) with main variable x and secondary variable y, I want
> to get the specialization f(r,y) for some r in Fp. It seems like the
> function I should use is:
>
> GEN FpXY_evaly(GEN Q, GEN y, GEN p, long vy)
[...]
Yes.
> When I try to call this function, the return value is always 1. For
> example, the following code
>
> #include "stdio.h"
> #include <pari/pari.h>
>
> int main()
> {
> pari_init( 400000000, 0 );
>
> int y = fetch_user_var( "y" );
> GEN p = utoi( 7 );
>
> GEN f = gp_read_str( "x^2 + y^2 + x*y + 1" );
> pari_printf( "f(x,y) = %Ps\n", f );
> printf( "gvar( f ) = %li\n", gvar( f ) );
>
> GEN fx0 = FpXY_evalx( f, gen_0, p );
> pari_printf( "f(x,0) = %Ps\n", fx0 );
>
> GEN f0y = FpXY_evaly( f, gen_0, p, y );
> pari_printf( "f(0,y) = %Ps\n", f0y );
>
> }
Your code is correct. There is a bug in FpXY_evaly when evaluating at 0
(and the degree is not 1).
I just pushed a fix to 'master' (commit 5f7a0ee9)
> Produces this output:
>
> f(x,y) = x^2 + y*x + (y^2 + 1)
> gvar( f ) = 0
> f(x,0) = x^2 + 1
> f(0,y) = 1
>
>
> The last line should be y^2 + 1. Am I using the function correctly?
Yes. Please update from master :-)
> Alternatively, I know I could use the functions gsubst or poleval and then
> reduce mod p, but wouldn't that be slower? p may be very large and f
> may have high degree.
Possibly much slower, due to intermediate expression swell.
Somewhat analogous to the (simplest) example:
setrand(1); b = 100000;
y = random(1<<b);
x = random(1<<b) % y;
n = 100;
Mod(x,y)^n; \\ 120ms
x^n % y; \\ 4,709ms
Cheers,
K.B.
--
Karim Belabas, IMB (UMR 5251) Tel: (+33) (0)5 40 00 26 17
Universite de Bordeaux Fax: (+33) (0)5 40 00 69 50
351, cours de la Liberation http://www.math.u-bordeaux1.fr/~kbelabas/
F-33405 Talence (France) http://pari.math.u-bordeaux1.fr/ [PARI/GP]
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