Kevin Ryde on Tue, 16 Dec 2014 11:19:21 +0100


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Re: polynomial partial fractions 

Karim Belabas <Karim.Belabas@math.u-bordeaux.fr> writes:
>
>   C = vector(#P, i, Mod(B \/ PE[i], PE[i]));
>   [Q, vector(#P, i, padic(lift(A/C[i]), P[i])), PE];

Nice.  I don't think I knew to go by poly inverses before.  How does
that rate against a matsolve()?  About the same but less taking apart
and putting back together polynomials perhaps?