Re: bnfisintnorm: missing units in bnf

[Aurel Page <aurel.page@normalesup.org>]

Hi Max,

When the fundamental units of a number field are very large, bnfinit 
does not compute them by default, but they are needed for bnfisintnorm. 
Try bnfinit(x^2-28057,1);

Best,
Aurel

On 02/11/17 21:57, Max Alekseyev wrote:
> Hello!
>
> What this error is about?
>
> ? b=bnfinit(x^2-28057);
> ? bnfisintnorm(b,6259853216)
>   ***   at top-level: bnfisintnorm(b,6259853216)
>   ***                 ^--------------------------
>   *** bnfisintnorm: missing units in bnf.
>   ***   Break loop: type 'break' to go back to GP prompt
>
>
> Regards,
> Max