Peter Pein on Mon, 09 Jul 2018 14:17:27 +0200


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Re: Truncation Precision in PARI 

that is not very accurate :(

I get:

precision(-1 - Euler + 3/2*log(2*Pi) + 6*zetahurwitz(-1, 1, der = 1), 100)
%1 =
0.1870730725097797894509591576777666319578148029622159376465535484192711630046534855901322306210633101

or via series devel. of the summand w.r.t. k and changing the order of
summation:

 sumalt(n=2,(-1)^n*(n-1)/(n+2)*zeta(n))
%2 =
0.1870730725097797894509591576777666319578148029622159376465535484192711630046534855901322306210633101

(which evaluates fast)

Peter