Curiosity

Andrea Ribuoli on Thu, 07 Jan 2021 21:05:23 +0100

Curiosity

To: pari-users@pari.math.u-bordeaux.fr
Subject: Curiosity
From: Andrea Ribuoli <andrea.ribuoli@yahoo.com>
Date: Thu, 7 Jan 2021 21:05:13 +0100
Delivery-date: Thu, 07 Jan 2021 21:05:23 +0100
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Good evening,

I have installed PariGP and tried -in sequence- the following calculations (manually extending the number of iterations):

            c=0.0; for (i=1,    1000000, c=c+bigomega(i); print(c/i))  

3.626619...

            c=0.0; for (i=1,   10000000, c=c+bigomega(i); print(c/i))  

3.786124...

            c=0.0; for (i=1,  100000000, c=c+bigomega(i); print(c/i))  

3.923512...

            c=0.0; for (i=1, 1000000000, c=c+bigomega(i); print(c/i))  

4.044220...

Is it possible to use PariGP to guess the limit of (c/i) for i => ∞ ?

Regards,

Andrea

Follow-Ups:
- Re: Curiosity
  - From: Karim Belabas <Karim.Belabas@math.u-bordeaux.fr>