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Bill Allombert on Wed, 29 Jan 2025 22:08:02 +0100
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- To: pari-users@pari.math.u-bordeaux.fr
- Subject: Re: 2^[1,3]
- From: Bill Allombert <Bill.Allombert@math.u-bordeaux.fr>
- Date: Wed, 29 Jan 2025 22:07:57 +0100
- Delivery-date: Wed, 29 Jan 2025 22:08:02 +0100
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- In-reply-to: <Z5pAbp1TOsX6J7jQ@seventeen>
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On Wed, Jan 29, 2025 at 03:51:26PM +0100, Bill Allombert wrote:
> On Wed, Jan 29, 2025 at 03:24:02PM +0100, Ruud H.G. van Tol wrote:
> >
> > On 2025-01-29 14:42, Bill Allombert wrote:
> > > On Wed, Jan 29, 2025 at 02:28:46PM +0100, Ruud H.G. van Tol wrote:
> >
> > >> ? vecsum(2^[1,3])
> > >> % 10.000000000000000000000000000000000000
I geuss you can do vecsum([2^i|i<-[1,3]])
Cheers,
Bill.
- Follow-Ups:
- Re: 2^[1,3]
- From: "Ruud H.G. van Tol" <rvtol@isolution.nl>
- References:
- 2^[1,3]
- From: "Ruud H.G. van Tol" <rvtol@isolution.nl>
- Re: 2^[1,3]
- From: Bill Allombert <Bill.Allombert@math.u-bordeaux.fr>
- Re: 2^[1,3]
- From: "Ruud H.G. van Tol" <rvtol@isolution.nl>
- Re: 2^[1,3]
- From: Bill Allombert <Bill.Allombert@math.u-bordeaux.fr>