| Bill Allombert on Mon, 17 Feb 2025 20:23:55 +0100 |
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| Re: How to find a solution to this equation so the result is a perfect square ? |
On Thu, Feb 13, 2025 at 03:05:30PM +0100, Laël Cellier wrote: > So, do you mean only square roots of a are the solution ? In the current > example, I volontarily took a long a in the case it’s hard to factorize (up > to 1024). On the other end, I don’t need a specific end result, but just for > it to be a square… > > And even then, what about the case I know a square root > of 20422354090808007360481140437163150058277495681745577657420405131241 mod > 53919893334301279589334030174040979997534463873026188556492192357233 (taking > back the example) ? Unless 20422354090808007360481140437163150058277495681745577657420405131241 is special, there is no hope: N=53919893334301279589334030174040979997534463873026188556492192357233 A=random(N) B=A^2%N So now I have B and a squareroot A of B mod N. But of course this gives no new information on N. Cheers, Bill.