| Bill Allombert on Thu, 23 Oct 2025 15:57:07 +0200 |
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| Re: Question on finding a Riemann Zeta function zero for high values of s |
On Thu, Oct 23, 2025 at 11:38:43AM +0200, Cohen Henri wrote: > > Second attempt at a patch, the first was wrong. Replace the computation of p1 by > p1 = gsub(gmul(pmd, mulcxI(gsqr(zn))), gmul(s, glog(zn, prec))); > p1 = gmul(gexp(p1, prec), gmul(aleps, gadd(x, ix))); > > This at least gives the right result for the zero at height 10^11, and does not crash at 10^21. Your patch gives this ? s = 1/2 + 1370919909931995308226.68016095*I %1 = 1/2+1370919909931995308226.6801609500000000*I ? zeta(s) %2 = 4.0536436970172441408698440140242774312E-8+2.4195172994094734771061685252890615819E-8*I ? ## *** last result: cpu time 3h, 5min, 32,685 ms, real time 9min, 25,142 ms. (which is the same result as mine and looks OK given the input accuracy). A better approximation of s is ? s2 = 1/2+1370919909931995308226.68016095354847361*I; ? zeta(s2) %47 = -1.93955520903444813832202660734386359006E-15-1.15767118329892041096332490256606300204E-15*I Cheers, Bill